Asked by Amanda
Express 2x^3-9/x^3+6x^2+8x as partial fractions
Answers
Answered by
Steve
(2x^3-9)/(x^3+6x^2+8x)
= (2x^3-9) / (x)(x+2)(x+4)
= 2 - (9/8)/x + (25/4)/(x+2) - (137/8)/(x+4)
= (2x^3-9) / (x)(x+2)(x+4)
= 2 - (9/8)/x + (25/4)/(x+2) - (137/8)/(x+4)
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