Asked by Kiana

How many moles of compound are present in 17g of Fe2O3?

I think I know how to do this, so if someone can show me so I can check my work against it. My answer was .106 moles of Fe2O3.
Answered by DrBob222
Why don't you show how you did it ans let us check your work.
Answered by Kiana
Well, If Fe atomic mass is 55.85 and O is 16, then multipy 55.85 by two and 16 by 3 and get 159.7 g/mol. Then divide 17g by 159.7 g/mol and get .106 moles.
Answered by DrBob222
You are absolutely correct. Good work.
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