Asked by Emily Ann
What is the average useful power output of a person who does 5.90×106 J of useful work in 7.90 h?
I got 207 W
Working at this rate, how long will it take this person to lift 2400 kg of bricks 1.30 m to a platform? (Work done to lift his body can be omitted because it is not considered useful output here.)
This is the part I need help with, please. Thanks!
I got 207 W
Working at this rate, how long will it take this person to lift 2400 kg of bricks 1.30 m to a platform? (Work done to lift his body can be omitted because it is not considered useful output here.)
This is the part I need help with, please. Thanks!
Answers
Answered by
Henry
a. My answer: 207.5 J/s = 207.5 W.
b. Work = F*d = Mg*d = 2400*9.8 * 1.3 = 30,576 Joules.
T = 30,576J. * 1s./207.5J. = 147.4 s.
b. Work = F*d = Mg*d = 2400*9.8 * 1.3 = 30,576 Joules.
T = 30,576J. * 1s./207.5J. = 147.4 s.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.