a. My answer: 207.5 J/s = 207.5 W.
b. Work = F*d = Mg*d = 2400*9.8 * 1.3 = 30,576 Joules.
T = 30,576J. * 1s./207.5J. = 147.4 s.
What is the average useful power output of a person who does 5.90×106 J of useful work in 7.90 h?
I got 207 W
Working at this rate, how long will it take this person to lift 2400 kg of bricks 1.30 m to a platform? (Work done to lift his body can be omitted because it is not considered useful output here.)
This is the part I need help with, please. Thanks!
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