Asked by Dina
1300 kg car rounds a banked curve of radius= 50m. If car traveling at 75 km/h and the coefficient of static friction between the tire and road is 0.45 ...
1.) what is the minimum angle of the bank needed to keep the car in the turn?
2.) If the car changes tires, which increases the Coef. of Friction to 0.65.
3.) What will be the max. Velocity for the car to be able to turn (assuming the same banked angle)?
1.) what is the minimum angle of the bank needed to keep the car in the turn?
2.) If the car changes tires, which increases the Coef. of Friction to 0.65.
3.) What will be the max. Velocity for the car to be able to turn (assuming the same banked angle)?
Answers
Answered by
Chanz
This one is almost impossible to do without the FBD in front of you. In this problem the mg force is down the normal is purpendicular to the track and friction is parallel to the track.
Equation in y:
Fn cosθ + Ff sinθ = mg
Equation in x (causing circ motion):
Fn sinθ - Ff cosθ = mv^2/r
Third eq you need mu Fn = Ff
Now you have three eqs and three unknowns.The math is less than delightful.
Equation in y:
Fn cosθ + Ff sinθ = mg
Equation in x (causing circ motion):
Fn sinθ - Ff cosθ = mv^2/r
Third eq you need mu Fn = Ff
Now you have three eqs and three unknowns.The math is less than delightful.
Answered by
Chanz
Sorry, that should be
y direction:
Fn cosθ = mg + Ffsinθ
x direction:
Fn sinθ + Ff cosθ = mv^2/r
And:
mu Fn = Ff
We're trying to not fly off the track.
I get a value of about 17.1o which seems reasonable.
y direction:
Fn cosθ = mg + Ffsinθ
x direction:
Fn sinθ + Ff cosθ = mv^2/r
And:
mu Fn = Ff
We're trying to not fly off the track.
I get a value of about 17.1o which seems reasonable.
Answered by
dina
How did you get 17.1
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.