Asked by david
integrate:dz/(z^2+1)
where z is a complex number.....plz working
where z is a complex number.....plz working
Answers
Answered by
Steve
this is a standard form.
Let
z = tanθ
z^2+1 = sec^2θ
dz = sec^2θ dθ
Plug that in and see how simple it is.
You can also use
z = sinhθ
but that's less common.
Let
z = tanθ
z^2+1 = sec^2θ
dz = sec^2θ dθ
Plug that in and see how simple it is.
You can also use
z = sinhθ
but that's less common.
Answered by
david
what the meaning of that box
Answered by
Steve
Hmmm. font problem, I guess. It's theta.
Let's use t
z = tan(t)
z^2+1 = sec^2(t)
dz = sec^2(t) dt
Let's use t
z = tan(t)
z^2+1 = sec^2(t)
dz = sec^2(t) dt
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