I am going to assume that the roof is 96 ft high, not 9696, and you want to know when the ball is 48 ft high, not 4848
so 48 = -16t^2 + 8t + 96
(the equation implies it was tossed upwards with a velocity of 8 ft/sec)
16t^2 - 8t - 48 = 0
2t^2 - t - 6 = 0
(2t + 3)(t - 2) = 0
t = -3/2 or t = 2
but t ≥ 0
the ball was 48 ft high after 2 seconds
A ball is thrown straight up from a rooftop 9696 feet high. The formula below describes the ball's height above the ground, h, in feet, t seconds after it was thrown. The ball misses the rooftop on its way down. The graph of the formula is shown. Determine when the ball's height will be 4848 feet and identify the solution as a point on the graph.
h equals negative 16 t squared plus 8 t plus 96h=−16t2+8t+96
1 answer
1 answer