Asked by Rose

Find the middle term in the expansion of (2x+3y)^12
Answered by Reiny
There will be 13 terms, so the middle term is term #7
Term(7) = C(12,6)(2x)^6 (3y)^6
= 924(64x^6)(729y^6)
= 43110144 x^6 y^6
Answered by Saidi
The formula to find a middle term
Answered by Saidi
No
Answered by kennedy
(2x-y^3)^23
Answered by kennedy
(2x-y^3)^12 find the middle term of the expension
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