Find the middle term in the expansion of (2x+3y)^12

Answer 1

There will be 13 terms, so the middle term is term #7
Term(7) = C(12,6)(2x)^6 (3y)^6
= 924(64x^6)(729y^6)
= 43110144 x^6 y^6

Answer 2

The formula to find a middle term

Answer 3

No

Answer 4

(2x-y^3)^23

Answer 5

(2x-y^3)^12 find the middle term of the expension