Asked by Rose
A game is played using three 6-sided dice. You throw these dice one time and if the dice all show the same number ( triples), you win $ 40.00 . For this game to be “fair”, how much should a person pay to play this game ?
Answers
Answered by
Damon
well lets figure out probability of all ones, then multiply by 6
1/6 * 1/6 * 1/6 = 1/6^3
now probability of three of any old number is
6/6^3 = 1/36
40/36 = $1.11111 but long term the house should come out ahead :)
so
$1.12
1/6 * 1/6 * 1/6 = 1/6^3
now probability of three of any old number is
6/6^3 = 1/36
40/36 = $1.11111 but long term the house should come out ahead :)
so
$1.12
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