Asked by Rose
In the expansion of (ax +by)^8, the first three terms are 256x^8, 6144x^7y and 64512x^6y^2. Find the values of a and b
Answers
Answered by
bobpursley
a=256^1/8=2
2^7*b^1=6144, so b=6144/128=48
2^7*b^1=6144, so b=6144/128=48
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