Asked by Faith
A chemist mixes 96.8 g of ammonia, NH3, with 188 L of O2 at STP. How many grams of NO will be produced? The balanced equation for this reaction is:
4NH3 +5O2 = 4NO + 6H2O
4NH3 +5O2 = 4NO + 6H2O
Answers
Answered by
bobpursley
you will have molesNH3=96.8/17=5.69
according to the balanced equation, you need 5/4 (5.69)moles=7.11moles O2.
you have 188/22.4 molesO2=8.39molesO2, so you have plenty of oxygen. The reaction will exhaust the ammonia.
You should then get 5.69 moles of NO then. Convert that to grams.
according to the balanced equation, you need 5/4 (5.69)moles=7.11moles O2.
you have 188/22.4 molesO2=8.39molesO2, so you have plenty of oxygen. The reaction will exhaust the ammonia.
You should then get 5.69 moles of NO then. Convert that to grams.
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