Question

A chemist mixes 96.8 g of ammonia, NH3, with 188 L of O2 at STP. How many grams of NO will be produced? The balanced equation for this reaction is:

4NH3 +5O2 = 4NO + 6H2O
bobpursley
you will have molesNH3=96.8/17=5.69
according to the balanced equation, you need 5/4 (5.69)moles=7.11moles O2.
you have 188/22.4 molesO2=8.39molesO2, so you have plenty of oxygen. The reaction will exhaust the ammonia.

You should then get 5.69 moles of NO then. Convert that to grams.

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