distance by bus --- x km
distance walking -- 35-x km
x/5 + (35-x)/60 = 1.5
times 60
12x + 35-x = 90
11x = 55
x = 5
he walked 5 km, and went 30 km by bus
check:
time walking = 5/5 = 1 hr
time on bus = 30/60 = 1/2 hr
total is 1.5 hrs
distance walking -- 35-x km
x/5 + (35-x)/60 = 1.5
times 60
12x + 35-x = 90
11x = 55
x = 5
he walked 5 km, and went 30 km by bus
check:
time walking = 5/5 = 1 hr
time on bus = 30/60 = 1/2 hr
total is 1.5 hrs
Let's assume that Yochanan covered x kilometers by walking and (35 - x) kilometers by traveling on the bus.
We are given that Yochanan's average speed while walking was 5 km/h. Therefore, the time taken to walk the distance x kilometers can be calculated as x/5 hours.
We are also given that Yochanan's average speed on the bus was 60 km/h. Therefore, the time taken to travel the distance (35 - x) kilometers on the bus can be calculated as (35 - x)/60 hours.
The total time taken for the entire trip is given as 1.5 hours. So, we can set up the following equation:
x/5 + (35 - x)/60 = 1.5
To solve this equation, we can multiply through by the least common multiple (LCM) of 5 and 60, which is 60:
60*(x/5) + 60*((35 - x)/60) = 60*1.5
Simplifying, we get:
12x + 35 - x = 90
Combining like terms, we obtain:
11x + 35 = 90
Subtracting 35 from both sides, we have:
11x = 55
Dividing both sides by 11, we find:
x = 5
Now, we know that Yochanan covered 5 kilometers by walking and (35 - 5) = 30 kilometers by traveling on the bus.