Asked by Angel
This is similar to a question i seen below but how do i write cos^2 4-sin^2 4 as a single trigonometric function?
And 1-2sin^2 3
And 1-2sin^2 3
Answers
Answered by
Reiny
Have you come across this identity and its variations?
cos 2A = cos^2 A - sin^2 A
= 1 - 2sin^2 A
= 2cos^2 A - 1
so ....
cos^2 4-sin^2 4
= 1 - sin^2 4 - sin^2 4
= 1 - 2sin^2 4
= cos 8
1 - 2sin^2 3
= cos 6
cos 2A = cos^2 A - sin^2 A
= 1 - 2sin^2 A
= 2cos^2 A - 1
so ....
cos^2 4-sin^2 4
= 1 - sin^2 4 - sin^2 4
= 1 - 2sin^2 4
= cos 8
1 - 2sin^2 3
= cos 6
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