Asked by maryam

A police car moving at 75m/s is initially behind a truck moving in the same direction at 14m/s. The natural frequency of the car's siren is 1000Hz.

What is the change in frequency observed by the truck driver as the car overtakes him?
Answered by Henry
Fr = (Vs+Vt)/(Vs-Vc)*Fc =
(443+14)/(443-75) * 1000 = 457/368 * 1000 = 1242 Hz. = Freq.
heard by the receiver(Truck driver).















Answered by Henry
Correction: Vs = 343 m/s.

(343+14)/(343-75) * 1000 = 357/268 * 1000 = 1332 Hz.

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