Asked by Maria

Equilibrium involving SO2(g), O2(g) & SO3(g) is important in sulfuric acid production. When a 0.0200 mol sample of SO3 is introduced into an evacuated 1.52 L vessel at 900 K, 0.0142 mol, SO3 is found to be present at equilibrium. What is the value of Kp for the dissociation of SO3(g) at 900 K?

Answers

Answered by DrBob222
Use PV = nRT and solve for pSO3 at the beginning and at equilibrium. I obtained about 1 for pSO3 initially but you need to get a more accurate answer.
Then
..........2SO3 ==> 2SO2 + O2
I.........1.0.......0......0
C.........-2x.......2x.....x
E........1.0-2x.....2x.....s

The problem tells you that 1.0-2x (or whatever more accurate answer you get for that 1.0 number) = pSO3 at equilibrium. You get that number from the 0.142 mol and PV = nRT.
Evaluate each equilibrium value from above and substitute into the Kp expression. Solve for Kp.
Answered by Anonymous
0.236

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