Suppose the integral from 2 to 8 of g of x, dx equals 5, and the integral from 6 to 8 of g of x, dx equals negative 3, find the value of the integral from 2 to 6 of 2 times g of x, dx .

Question

8 MY ANSWER

12

16

4

Answer 1

Hmmm. Let's trudge through those words. We have

∫[2,8] g(x) dx = 5
∫[6,8] g(x) dx = -3

we know that

∫[2,6] + ∫[6,8] = ∫[2,8]
∫[2,6] + (-3) = 5
∫[2,6] g(x) = 8
∫[2,6] 2g(x) = 2*8 = 16

Forgot that 2, eh?