Asked by Lilly
Suppose the integral from 2 to 8 of g of x, dx equals 5, and the integral from 6 to 8 of g of x, dx equals negative 3, find the value of the integral from 2 to 6 of 2 times g of x, dx .
8 MY ANSWER
12
16
4
8 MY ANSWER
12
16
4
Answers
Answered by
Steve
Hmmm. Let's trudge through those words. We have
∫[2,8] g(x) dx = 5
∫[6,8] g(x) dx = -3
we know that
∫[2,6] + ∫[6,8] = ∫[2,8]
∫[2,6] + (-3) = 5
∫[2,6] g(x) = 8
∫[2,6] 2g(x) = 2*8 = 16
Forgot that 2, eh?
∫[2,8] g(x) dx = 5
∫[6,8] g(x) dx = -3
we know that
∫[2,6] + ∫[6,8] = ∫[2,8]
∫[2,6] + (-3) = 5
∫[2,6] g(x) = 8
∫[2,6] 2g(x) = 2*8 = 16
Forgot that 2, eh?
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