Asked by Anon

A 313 μF defibrillator capacitor is charged to 4.94×103 V. When fired through a patients chest, it loses 95 % of its charge in 40 ms.

What is the resistance of the patients chest?
Answered by Chanz
i = Q/t but we need Q
Q = VC
Actual Q will be %95 of that.
Then V = iR
solve for R
There are no AI answers yet. The ability to request AI answers is coming soon!