Asked by Anon
A 313 μF defibrillator capacitor is charged to 4.94×103 V. When fired through a patients chest, it loses 95 % of its charge in 40 ms.
What is the resistance of the patients chest?
What is the resistance of the patients chest?
Answers
Answered by
Chanz
i = Q/t but we need Q
Q = VC
Actual Q will be %95 of that.
Then V = iR
solve for R
Q = VC
Actual Q will be %95 of that.
Then V = iR
solve for R
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.