1.0 mol of each of the gases, CO, H20, CO2 and H2 are placed in a 2.00L container and allowed to reach equilibrium. It is found at equilibrium 0.40 mol of CO is present. Calculate the value of K eq for the system.

Question

1.0 mol of each of the gases, CO, H20, CO2 and H2 are placed in a 2.00L container and allowed to reach equilibrium. It is found at equilibrium 0.40 mol of CO is present. Calculate the value of K eq for the system. 
C0(g) + H20(g)--- CO2(g) + H2(g) 
Intial 
CO= 0.5 mol/L 
H20= 0.5 mol/L 
CO2= 0.5 mol/L 
H2= 0.5 mol/L 
change 
CO= -0.1 
H20= -0.1 
C02= +0.1 
H2= +0.1 
Equilibrium 
C0= 0.40 mol/L 
H20=0.40 mol/L 
CO2= 0.6 mol/L 
H2=0.6 mol/L 
k eq= (C02)(H2)/(C0)(H20) 
= (0.6)(0.6)/(0.4)(0.4)= 2.25