Asked by Anonymous
The threshold wavelength for photoelectric emission in metal is 600 nm.Find the maximum kinetic energy of the electrons emitted when it is exposed to the wavelength 200 nm
Answers
Answered by
bobpursley
KE of emission=energyIncident-workfunction
workfuncion=hc/600nm solve that in joules
then energy incident=hc/200nm
KE=hc(1/200-1/600)1/nm=hc/1E-9 (4 /600)=4*E-9*hc/600
workfuncion=hc/600nm solve that in joules
then energy incident=hc/200nm
KE=hc(1/200-1/600)1/nm=hc/1E-9 (4 /600)=4*E-9*hc/600
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