Asked by Anonymous

The threshold wavelength for photoelectric emission in metal is 600 nm.Find the maximum kinetic energy of the electrons emitted when it is exposed to the wavelength 200 nm

Answers

Answered by bobpursley
KE of emission=energyIncident-workfunction

workfuncion=hc/600nm solve that in joules

then energy incident=hc/200nm

KE=hc(1/200-1/600)1/nm=hc/1E-9 (4 /600)=4*E-9*hc/600
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