A solid sphere of uniform density starts from rest and rolls without slipping a distance of d = 4.8 m down a θ = 36° incline. The sphere has a mass M = 3.2 kg and a radius R = 0.28 m. If there is no frictional force, what is the translational kinetic energy of the sphere at the bottom of the incline?

asked by Kyle

9 years ago

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1 answer

mgh = 7/10 mv^2
Use trig to find h
solve for v
find 1/2 mv^2

answered by Chanz

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1

Question

A solid sphere of uniform density starts from rest and rolls without slipping a distance of d = 4.8 m down a θ = 36° incline. The sphere has a mass M = 3.2 kg and a radius R = 0.28 m. If there is no frictional force, what is the translational kinetic energy of the sphere at the bottom of the incline?

1 answer

mgh = 7/10 mv^2
Use trig to find h
solve for v
find 1/2 mv^2

Chanz · Answer

mgh = 7/10 mv^2 Use trig to find h solve for v find 1/2 mv^2