Asked by Bridget

so im not that good with word problems so... here it goes.

Nadine has 7 more nickles than Delano has dimes. If Delano gives Nadine 4 of his dimes, then Delano will have the same amountof money as Nadine. How much money do they have together, assuming Nadine only has nickles and Delano only has dimes?
Answered by Damon
dimes = d
nickles = (d+7)
then later
(d-4)(.1) = (d+7)(.05)+4(.1)
Answered by Bridget
would that be the same as
.05(d+7)=(d-4).1 ?
Answered by Damon
no, you need to credit Nadine with 4 dimes (4)(.1)
Answered by Bridget
oooh!!! ok, thank you!!! so then i would get
.1d - .4 = .05d + .35 + .4
.1d - .4 = .05d + .75
.05d - .4 = .75
.05d = 1.15
d = 23
right???
Answered by Damon
looks good
Answered by Bridget
ok, thank you sooo much!!! :)
Answered by erick
-3y+4=8y-4+6y
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