Asked by Nevaeh
What is the final temperature and physical state if water when 47.50 kJ of energy is added to 15.0 g of ice at -10.0 C?
Helpful information:
Cs (ice) = 2.1 J/g C
Heat of fusion (water) = 6.02 kJ/mol
Cs (water) = 4.184 J/g C
Heat of vaporization (water) = 40.7 kJ/mol
Cs (steam) = 2.0 J/g C
Please check my answers below.
My answer:
Tf = 167.9 C
Physical state of water = gas
Helpful information:
Cs (ice) = 2.1 J/g C
Heat of fusion (water) = 6.02 kJ/mol
Cs (water) = 4.184 J/g C
Heat of vaporization (water) = 40.7 kJ/mol
Cs (steam) = 2.0 J/g C
Please check my answers below.
My answer:
Tf = 167.9 C
Physical state of water = gas
Answers
Answered by
DrBob222
I get 167 but that difference may be due to rounding errors.
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