Asked by bliss
Given the equation below, if 3.87×1023 particles of Sb2S3(s) are reacted with excess Fe(s), what mass of FeS(s) is produced?
Sb2S3(s) + 3Fe(s)→2Sb(s) +3FeS(s)
Sb2S3(s) + 3Fe(s)→2Sb(s) +3FeS(s)
Answers
Answered by
DrBob222
mols Sb2S3 = 3.87E23/6.02E23 = ?
Then mols Sb2S3 x (3 mols FeS/1 mol Sb2S3) = ?
Finally, grams = mols x molar mass
Then mols Sb2S3 x (3 mols FeS/1 mol Sb2S3) = ?
Finally, grams = mols x molar mass
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.