Question

3. For the reaction between Cu and Sn the potentials are given below;
Cu2+(aq) +2e- -----------> Cu(s) Eºcathode = 0.34 (half-cell potential)
Sn(s) -----------> Sn2+(aq) + 2 e- Eºanode = - 0.14 (half-cell potential)
Calculate the E.M.F (Voltage) of the cell
Calculate pH given [H+] = 1.4 x 10-5 M,
Find [H+] if pH = 8.5
EMF = ? Add the oxidation half to the reduction half.

Use pH = -log (H^+) for the other two.

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