Asked by Mr. Alexander
Find a base 7 three-digit number which has its digits reversed when expressed in base 9.
(You do not need to indicate the base with a subscript for this answer.)
(You do not need to indicate the base with a subscript for this answer.)
Answers
Answered by
Steve
well, using base 10 for now, if the number has base7 digits abc, we need
49a+7b+c = 81c+9b+a
c = 3a/5 - b/40
40c = 24a-b
If c=1, a=2,b=8 Nope
If c=2, a=4,b=16 Nope
If c=3, a=5,b=0
503<sub><sub>7</sub></sub> = 305<sub><sub>9</sub></sub>
check:
49*5+3 = 81*3+5
yes
49a+7b+c = 81c+9b+a
c = 3a/5 - b/40
40c = 24a-b
If c=1, a=2,b=8 Nope
If c=2, a=4,b=16 Nope
If c=3, a=5,b=0
503<sub><sub>7</sub></sub> = 305<sub><sub>9</sub></sub>
check:
49*5+3 = 81*3+5
yes
Answered by
Person
That would be wrong, sorry.
Answered by
Minecraft Bot
thats actually correct you know?
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