Asked by fagi

Find the restrictions:
how to solve problem
1. y = 3- sqrt(2x-8)

x => 0

2. y = 9-sqrt(x -2)

x =>0
Answered by Reiny
#1
2x-8 ≥ 0
2x≥ 8
x ≥ 4

#2
x-2 ≥ 0
x ≥ 2
Answered by fagi
where is 3 goes?
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