Asked by David
A 50 kg cannonball hits a war tank vehicle of 12,000 kg that is initially at rest. The cannonball embeds in the tank and both move at the same velocity for 50 cm until they both come to a rest. What is the initial velocity of the cannonball if the coefficient of friction between the tank and the pavement is 0.25?
Answers
Answered by
Chanz
War tank vehicle...very manly sounding.
Anyway.
Consvrtn of momentum:
m1v1i = (m1+m2)vf
So we need vf
Our friction force is mu*Fn and Fn is just mg (12050*9.8) so Ff = .25*12050*9.8.
So the work done (which is equal to KE lost) is Ff*d = 12050*9.8*.25*.5
that equals 1/2 m vf^2 so solve for vf. Plug that back into your conservation of momentum eq and there you are.
Anyway.
Consvrtn of momentum:
m1v1i = (m1+m2)vf
So we need vf
Our friction force is mu*Fn and Fn is just mg (12050*9.8) so Ff = .25*12050*9.8.
So the work done (which is equal to KE lost) is Ff*d = 12050*9.8*.25*.5
that equals 1/2 m vf^2 so solve for vf. Plug that back into your conservation of momentum eq and there you are.
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