Asked by Ibrahim
Two point charges 2uC and 8uC are placed 12 cm apart. Find the position of the point where electric field resultant will be zero
Answers
Answered by
Damon
2/x^2 = 8/(12-x)^2
1/x^2 = 4 /(12-x)^2
4 x^2 = 144 - 24 x + x^2
3 x^2 + 24 x - 144 = 0
x^2 + 8 x - 48 = 0
(x+12)(x-4) = 0
x = 4 cm
then 12 - x = 8 cm
check
2/16 = 8/64 ??? yes right
1/x^2 = 4 /(12-x)^2
4 x^2 = 144 - 24 x + x^2
3 x^2 + 24 x - 144 = 0
x^2 + 8 x - 48 = 0
(x+12)(x-4) = 0
x = 4 cm
then 12 - x = 8 cm
check
2/16 = 8/64 ??? yes right
Answered by
Chanz
r is the point where they cancel
E1 = kq1/r^2
E2 = kq2/(.12-r)^2
Drop the k's set them equal and solve for r. You'll have to cross multiply and solve the quadratic.
E1 = kq1/r^2
E2 = kq2/(.12-r)^2
Drop the k's set them equal and solve for r. You'll have to cross multiply and solve the quadratic.
Answered by
Ritu
Nothing
Answered by
sneha
Nothing
Answered by
Rahul
Thanks
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