Asked by Ibrahim
                Two point charges 2uC and 8uC are placed 12 cm apart. Find the position of the point where electric field resultant will be zero 
            
            
        Answers
                    Answered by
            Damon
            
    2/x^2 = 8/(12-x)^2
1/x^2 = 4 /(12-x)^2
4 x^2 = 144 - 24 x + x^2
3 x^2 + 24 x - 144 = 0
x^2 + 8 x - 48 = 0
(x+12)(x-4) = 0
x = 4 cm
then 12 - x = 8 cm
check
2/16 = 8/64 ??? yes right
    
1/x^2 = 4 /(12-x)^2
4 x^2 = 144 - 24 x + x^2
3 x^2 + 24 x - 144 = 0
x^2 + 8 x - 48 = 0
(x+12)(x-4) = 0
x = 4 cm
then 12 - x = 8 cm
check
2/16 = 8/64 ??? yes right
                    Answered by
            Chanz
            
    r is the point where they cancel
E1 = kq1/r^2
E2 = kq2/(.12-r)^2
Drop the k's set them equal and solve for r. You'll have to cross multiply and solve the quadratic.
    
E1 = kq1/r^2
E2 = kq2/(.12-r)^2
Drop the k's set them equal and solve for r. You'll have to cross multiply and solve the quadratic.
                    Answered by
            Ritu
            
    Nothing
    
                    Answered by
            sneha
            
    Nothing
    
                    Answered by
            Rahul
            
    Thanks
    
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