Tall buildings are flexible and undergo simple harmonic motion (SMH) when excited by wind. Suppose the top floor of a skyscraper is in SMH, swaying back and forth with a frequency of 0.181 Hz and an amplitude of 1.5 m.

a.What is the maximum speed experienced by top floor occupants?

b.What is the maximum acceleration experienced by top floor occupants?

1 answer

x = 1.5 sin (2 pi * .181 t)
= 1.5 sin (1.137 t)

v = dx/dt = 1.5* 1.137 cos (1.137 t)

v max = 1.5 * 1.137

a = d^2x/dt^2 = -1.5*1.137^2 sin (1.137 t)

a max = 1.5 * 1.137^2