Asked by Charles

Find the sum of vectors A=5m<60degree and B=6m<130degree
Answered by Chanz
x: 5cos60 +6cos130
y: 5sin60 + 6sin130
Pythag..and tan-1
Answered by Stone Temiloluwa
Solve the question for me
Answered by Stone imelda
The question is complicated
A=5m<60°
B=6m <130°
Answered by Maurice Osuji
c²=a²+b²-2a cos110°
=25+36-2(5)(6)cos110°
=81.52=c=9.02

Using sine rule we have
SinB/b =Sin110/c
Sin B = b/c X sin110
= 6/9.02 (0.9397) = 0.62446
Therefore. B = 38.64°

c makes an Angle 60° +38.64° =98.6425° with horizontal,that is c = 9.02m<99° .
Answered by Blest
How come about the 81.52
Answered by Debbie
How did u come about with cos 110°
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