.25" : 3' = 1":12'
so,
2"x3" = 24'x36' =
so,
2"x3" = 24'x36' =
If the actual length is 18 feet, what is the drawing length?
Let's start with the width of the pool. It is represented by 2 inches on the scale drawing. According to the scale, 0.25 inches on the drawing corresponds to 3 feet in reality. So, we can set up a proportion to find the width:
(2 inches) / (0.25 inches) = (x feet) / (3 feet)
Cross multiplying, we get:
2 * 3 = 0.25 * x
6 = 0.25x
To solve for x, divide both sides of the equation by 0.25:
6 / 0.25 = x
x = 24
So, the width of the pool is 24 feet.
Similarly, we can find the length of the pool using the given scale. The length is represented by 3 inches on the scale drawing. Using the same proportion as before, we have:
(3 inches) / (0.25 inches) = (x feet) / (3 feet)
Cross multiplying:
3 * 3 = 0.25 * x
9 = 0.25x
Dividing both sides by 0.25:
9 / 0.25 = x
x = 36
Therefore, the length of the pool is 36 feet.
In conclusion, the actual dimensions of the pool are 24 feet by 36 feet.