Asked by Jermaine
A cylindrical tank with a circular base of 8m in diamante is being filled at 4m3/min. How fast is the level rising when it is half full?
Known:
d=8m
2r=d
r=d/2
d(v)/dt=4.0m3/min
Confusion: How to apply the "half full" concept.
Known:
d=8m
2r=d
r=d/2
d(v)/dt=4.0m3/min
Confusion: How to apply the "half full" concept.
Answers
Answered by
bobpursley
it is not clear to me the orientation of the cylinder. Vertical, or Horizontal?
Answered by
Jermaine
It is not specified in the question. It is a tank, so perhaps up right, vertical?
Answered by
Steve
if it is upright, then the fluid level rises at a constant rate.
The cross-section is 16π m^2, so
dh/dt = dV/dt / 16π = 4.0/16π = 1/(4π) m/min
The cross-section is 16π m^2, so
dh/dt = dV/dt / 16π = 4.0/16π = 1/(4π) m/min
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