Asked by zaranae
a basketball player makes 60% of the free throws that he attempts, except that if he has just tried and missed a free throw then his chances of making a second one go down to only 30%. what is the probability that he makes both attempts? what is the probability that he makes at least one attempt?
Answers
Answered by
John
To make both: .6 times .6 = .36
Make at least one of two:
1st 2nd
make .6 make .6 miss .4
miss .4 make .3 miss .7
Makes at least one means one or two made
(.6)(.6) + (.6)(.4) + (.4)(.3
multiply and sum and you should get your answer.
Make at least one of two:
1st 2nd
make .6 make .6 miss .4
miss .4 make .3 miss .7
Makes at least one means one or two made
(.6)(.6) + (.6)(.4) + (.4)(.3
multiply and sum and you should get your answer.
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