Asked by Lia
Calculate the value of the thermodynamic equilibrium constant for the following reactions at 25.0 °C.
(a) N2H4(g) + 2O2(g) 2NO(g) + 2H2O(g)
Kp =
H20=-228.6
NO= 86.69
N2H4= 159.3
02 = 0
(a) N2H4(g) + 2O2(g) 2NO(g) + 2H2O(g)
Kp =
H20=-228.6
NO= 86.69
N2H4= 159.3
02 = 0
Answers
Answered by
DrBob222
That are these? What are the units?
H20=-228.6
NO= 86.69
N2H4= 159.3
02 = 0
If this is delta G, then
dGrxn = (n*dGproducts)-(n*dG reactants)
Then dGrxn = -RTlnK
YOu know dGrxn, R, T, solve for K.
H20=-228.6
NO= 86.69
N2H4= 159.3
02 = 0
If this is delta G, then
dGrxn = (n*dGproducts)-(n*dG reactants)
Then dGrxn = -RTlnK
YOu know dGrxn, R, T, solve for K.
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