Asked by darren
Please help..
How to answer if..
2log8/6 + 2^2log3 - 2log12
Thank you so much
How to answer if..
2log8/6 + 2^2log3 - 2log12
Thank you so much
Answers
Answered by
Reiny
using these log rules:
log(ab) = loga + logb
log(a/b) = loga - logb
log( a^n) = nloga
Rewrite 2log8/6 + 2^2log3 - 2log12
as
log(64/36) + 4log3 - log144
= log(64/36) + log81 - log144
= log ( (64/36)(81)/144)
= log 1
= 0
log(ab) = loga + logb
log(a/b) = loga - logb
log( a^n) = nloga
Rewrite 2log8/6 + 2^2log3 - 2log12
as
log(64/36) + 4log3 - log144
= log(64/36) + log81 - log144
= log ( (64/36)(81)/144)
= log 1
= 0
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