Asked by Jane
A man is holding a gun 4 feet above the ground and fires into an open field. The bullet has an initial velocity of 300 feet per second and an initial angle of 30°. Find the range (the horizontal distance traveled before hitting the ground ) and the bullet's max height. Please show.
h(t)= h0 + vo t sinθ - 16t^2
h(t)= h0 + vo t sinθ - 16t^2
Answers
Answered by
Steve
man, you have the equation. As you know the parabola
h = at^2 + bt + c
has its vertex at t = -b/2a
So, just plug and chug.
As for the range, find t when h=0 and then recall that the (constant) horizontal velocity is
vo cosθ
h = at^2 + bt + c
has its vertex at t = -b/2a
So, just plug and chug.
As for the range, find t when h=0 and then recall that the (constant) horizontal velocity is
vo cosθ
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.