a. Impulse = 0.224 * 22 =
b. V = Vo + a*t = -22, 18 + a*0.06 = -22, 0.06a = -40, a = 667 m/s^2.
F = M*a = 0.224* (-667) =
A 0.224-kg volleyball approaches a player horizontally with a speed of 18.0 m/s. The player strikes the ball with her fist and causes the ball to move in the opposite direction with a speed of 22.0 m/s.
(a) What impulse is delivered to the ball by the player?
kg·m/s
(b) If the player's fist is in contact with the ball for 0.0600 s, find the magnitude of the average force exerted on the player's fist.
N
1 answer
1 answer