Asked by Tyler

A girl standing on a bridge throws a stone vertically downward with an initial velocity of 15.0 m/s into the river below. If the stone hit's the water 2.00 seconds later what is the height of the bridge above the water?

Answers

Answered by Henry
h = Vo*t + 0.5g*t^2
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions