An archer pulls her bowstring back 0.420 m by exerting a force that increases uniformly from zero to 240 N.

(a) What is the equivalent spring constant of the bow?
N/m

(b) How much work does the archer do in pulling the bow?
J

1 answer

work= INT force dx=INT 240x/.420 dx
work= 1/2 240*.420=120*.420

that equals 1/2 k x^2
120*.420=1/2 k .420^2
k= 240/.420 N/m