Asked by Beth
Rearrange for T and J;
n=(2J+1)exp(-(BJ(J+1))/(KT))
where B and K are constants
n=(2J+1)exp(-(BJ(J+1))/(KT))
where B and K are constants
Answers
Answered by
drwls
Here's how you would do it for T.
ln n = ln (2J+1) -BJ(J+1)/kT
ln [n/(2J+1)] = -BJ(J+1)/kT
kT = -BJ(J+1)/ln[n/(2J+1)]
Now divide both sides by k
Work similarly to solve for J
ln n = ln (2J+1) -BJ(J+1)/kT
ln [n/(2J+1)] = -BJ(J+1)/kT
kT = -BJ(J+1)/ln[n/(2J+1)]
Now divide both sides by k
Work similarly to solve for J
Answered by
Beth
I understand how you do it for T, but since there is more than one J, I don't understand how you make J the subject.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.