Asked by Bright

Two points C and P lie on a straight line such that C is due north of P.Another point T is 6km away from the line CP on a bearing of 150 degree from C and 40 degree from P.What is the length of the line CP?
Answered by Reiny
In my diagram, I have the perpendicular from T go PC meeting PC at S, giving me 2 right angled triangles.

In triangle CST:
tan30° = 6/CS
CS = 6/tan30

in triangle PST:
tan40° = 6/SP
SP = 6/tan40

PC = CS+SP
= ....

you do the button-pushing
Answered by Aisha
By sine rule
Answered by Anonymous
Pls can u draw the diagram?