Asked by nan

Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation v(t)= 6t2 − 18t + 12 (in feet/sec).

4
5<-my answer
6
−1
Answered by Steve
2t^3-9t^2+12t = 16-36+24 = 4
Answered by M
its not 4
Answered by LSS Correct Answer
I marked 5 and got it wrong.... Based on the Chegg answers, I have a feeling 4 is right.
Answered by bigmoto
Take the integral of velocity and u get distance as a function of time. Then plug 2 for t into that and you should get what LSS is saying. Please actually do the work and try to follow my steps...
Answered by Anonymous
The answer is 6 i just got i right
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