Asked by Tony
A curve is defined parametrically
x = 1 - √3 sin(2s)
y = cos(2s-1)
What is the gradient at s=(pi/6)
x = 1 - √3 sin(2s)
y = cos(2s-1)
What is the gradient at s=(pi/6)
Answers
Answered by
Steve
dy/dx = dy/ds / dx/ds
= -2sin(2s-1) / -2√3 cos(2s)
so, just plug in the value for s.
= -2sin(2s-1) / -2√3 cos(2s)
so, just plug in the value for s.
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