Asked by jan
my son is x year old ,in five years time i will be twice his age and both our ages will be multiples of 10.the sum of ages will be between 50 and 100.how old am i
Answers
Answered by
Henry
son's age : (x+5) in 5 years.
Parent's age: 2(x+5) in 5 years.
50 < ((x+5) + 2(x+5))< 100,
50 < (x+5 + 2x+10) < 100,
50 < 3x+15 < 100,
50-15 < 3x < 100-15,
35 < 3x < 85,
35/3 < x < 85/3.
11 2/3 < X < 28 1/3,
16 2/3 < x+5 < 33 1/3,
(x+5) = 20 years = The son's age.
2(x+5) = 40 years = The parent's age.
Parent's age: 2(x+5) in 5 years.
50 < ((x+5) + 2(x+5))< 100,
50 < (x+5 + 2x+10) < 100,
50 < 3x+15 < 100,
50-15 < 3x < 100-15,
35 < 3x < 85,
35/3 < x < 85/3.
11 2/3 < X < 28 1/3,
16 2/3 < x+5 < 33 1/3,
(x+5) = 20 years = The son's age.
2(x+5) = 40 years = The parent's age.
Answered by
3mk
55
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