Asked by Anonymous

s Patricia finds that the experimental
probability of her dog wanting to go outside between 4 p.m. and 5 p.m.
is 7/12. About what percent of the time does her dog not want to go out
between 4 p.m. and 5 p.m.?

Answers

Answered by Reiny
time the dog wants to go outside in that time frame = (7/12)(60) = 35 minutes

so not wanting to outside = 25 minutes

percentage of time not going out
= 25/60 = appr 42%
Answered by Garvin
42%
Answered by Layla
42#
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