s Patricia finds that the experimental

probability of her dog wanting to go outside between 4 p.m. and 5 p.m.
is 7/12. About what percent of the time does her dog not want to go out
between 4 p.m. and 5 p.m.?

3 answers

time the dog wants to go outside in that time frame = (7/12)(60) = 35 minutes

so not wanting to outside = 25 minutes

percentage of time not going out
= 25/60 = appr 42%
42%
42#