Your notation is unclear. It appears that you want to say
(x^−2/x^1)^p · (y^q/x)^2=xy
(x^-3)^p (y^q/x)^2 = xy
x^-(3p+2) y^(2q) = xy
equating powers, we have
3p+2 = -1
p = -1
2q = 1
q = 1/2
(x^−2/x^1)p · (y^q/x)2=xy
Simplify the following exponential equation to determine the values of p and q.
1 answer
1 answer