Asked by Pradeep
Please sir solve this...
6.3 gm of oxalic acid (eq. Wt.=63) is dissolved in 500 ml solution what will be the normality of the solution?
6.3 gm of oxalic acid (eq. Wt.=63) is dissolved in 500 ml solution what will be the normality of the solution?
Answers
Answered by
bobpursley
oxalic is monoprotic, so
N=moles/volume=(6.3/63)/.5
N=moles/volume=(6.3/63)/.5
Answered by
DrBob222
I don't believe H2C2O4 has an equivalent weight of 63. The molar mass is 90 and it is diprotic; therefore, the equivalent weight is 45.
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