Question

Suppose f(x)=5/(x-2). f'(5)=-5/9. Use this to find the equation of the tangent line to the curve y=5/x-2 at the point (5,(5/3)). write your answer in the form y=mx+b where m is the slope and b is the y-intercept. The equation of the tangent line is.....

Answer 1

equation of tangent:

y - 5/3 = (-5/9)(x - 5)

y = (-5/9)x + 25/9 + 5/3
y = (-5/9)x + 40/9

check my arithmetic