Asked by Danniela
Find derivative of function
g (t)=(6t^2+5)^3 (t^3-7)^4
thank you very much!
g (t)=(6t^2+5)^3 (t^3-7)^4
thank you very much!
Answers
Answered by
bobpursley
g(t)=u(t)v(t)
g'=u' v+ v'u
g'=3(6t^2+5)^2(12t)(t^3-7)^4+(6t^2+5)^3*4(t^3-7)(3t^2)
g'=u' v+ v'u
g'=3(6t^2+5)^2(12t)(t^3-7)^4+(6t^2+5)^3*4(t^3-7)(3t^2)
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