Asked by Russian Math
A pharmacist has an 18% alcohol solution. How much of this solution and how much water must be mixed together to make 10 liters of a 12% alcohol solution?
Answers
Answered by
Russian Math
PLEASE HALP ITS IMPOSSIBLE
Answered by
Russian Math
Current work:
.18x+0(10-x)=1.2
.18x+0(10-x)=1.2
Answered by
Reiny
To make 10 L in total you will need x L of the 18% solution and 10-x L of water.
.18x + 0(10-x) = .12(10)
.18x = 1.2
x = 1.2/.18 = 120/18 = 20/3
He needs 20/3 L or 6 2/3 L of water.
(btw, a Russian would never dilute his alcohol)
.18x + 0(10-x) = .12(10)
.18x = 1.2
x = 1.2/.18 = 120/18 = 20/3
He needs 20/3 L or 6 2/3 L of water.
(btw, a Russian would never dilute his alcohol)
Answered by
Mother Russia
@Reiny: THAT WAS A PHARMACIST... And also I go to a stupid math school. they make me do this.
Answered by
JohnCena
plz help how much solution does he need?
Answered by
krozavitz
help a Russian out, how much liters of water does he have?
Spasibo
Spasibo
Answered by
bobert
russian math sucks
Answered by
Anonymous
i need the liters of water
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