Asked by Rina
A 12-V automobile storage battery has an internal resistance of 0.004 ohms. A) Find the current and power dissipation when the terminals are connected by a conductor of negligible Resistance B) The battery delivers 80A to the starter motor. What resistance would draw the same current? C) How much power is supplied to the motor?
Answers
Answered by
Damon
i = V/R = 12 / .004 amps
P = i V = 144/R Joules
i = 80
R = V/i = 12/ 80
external resistance Rx = R - .004
power to motor = i^2 Rx = 6400 Rx
P = i V = 144/R Joules
i = 80
R = V/i = 12/ 80
external resistance Rx = R - .004
power to motor = i^2 Rx = 6400 Rx
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